2^x+32*2^(-3)=33

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Solution for 2^x+32*2^(-3)=33 equation: 



2^x+32*2^(-3)=33

We move all terms to the left:

2^x+32*2^(-3)-(33)=0

determiningTheFunctionDomain
2^x-33+32*2^(-3)=0

We add all the numbers together, and all the variables

2^x-29=0

We move all terms containing x to the left, all other terms to the right

2^x=29

x=29/1

x=29

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